JEE PHYSICS MCQ: SYSTEM OF PARTICLES

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Application +4 | -1

A thin uniform circular disc of mass

M

and radius

R

is rotating in a horizontal plane about an axis passing through its centre and perpendicular to its plane with an angular velocity

\omega

. Another disc of same thickness and radius but of mass

\frac{1}{8} \mathrm{M}

is placed gently on the first disc co-axially. The angular velocity of the system is now

View answer and explanation

Correct option: A

\frac{8}{9} \omega

Option A (

\frac{8}{9} \omega

) is correct because it is derived from the conservation of angular momentum when the second disc is placed on the first.

More Questions from SYSTEM OF PARTICLES

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\mathrm{AB}

\mathrm{L}

\mu(x)=a+\frac{b x}{L}

x

\mathrm{A}

\mathrm{CM}

\left(\frac{7}{12}\right) \mathrm{L}

\mathrm{A}

\mathrm{b}

1.0 \mathrm{~g}

8 \mathrm{~cm}

\omega = {t^4} + 2{t^3}

t = 1\,sec

\left( {rad\,{s^{ - 2}}} \right)