JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

1 Easy

1 of 1

Application +4 | -1

The value of the integral

\int\limits_{0}^{400 \pi} \sqrt{1-\cos 2 x} \, d x

, is

View answer and explanation

Correct option: C

800 \sqrt{2}

Option C is correct because the integral simplifies to

\int_0^{400\pi} \sqrt{2}|\sin x| dx

, and since

|\sin x|

is periodic with period

\pi

, the integral becomes

400\sqrt{2}\int_0^{\pi} \sin x dx = 800\sqrt{2}

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