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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Application +4 | -1
The solution for xx of the equation ∫2x1tt2−1dt=π2,\int\limits_ {\sqrt{2}}^x \frac{1}{t \sqrt{t^2-1}} d t=\frac{\pi}{2}, is
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Correct option: D
−2-\sqrt{2}
The correct answer is -2\sqrt{2}. The integral is solved using the inverse secant function, and solving for x gives -2\sqrt{2}.

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