KI and ${\rm{CuS}}{{\rm{O}}_4}$ solution when mixed, give

${{\rm{K}}_2}{\rm{S}}{{\rm{O}}_4} + {\rm{C}}{{\rm{u}}_2}{{\rm{I}}_2} + {{\rm{I}}_2}$

${\rm{Cu}}{{\rm{I}}_2} + {{\rm{K}}_2}{\rm{S}}{{\rm{O}}_4}$

${\rm{C}}{{\rm{u}}_2}{{\rm{I}}_2} + {{\rm{K}}_2}{\rm{S}}{{\rm{O}}_4}$

${{\rm{K}}_2}{\rm{S}}{{\rm{O}}_4} + {\rm{Cu}}{{\rm{I}}_2} + {{\rm{I}}_2}$

NEET UG CHEMISTRY MCQ: S-BLOCK ELEMENTS

1 Hard

1 of 1

Understanding +4 | -1

KI and

\mathrm{CuS}{\mathrm{O}_4}

solution when mixed, give

View answer and explanation

Correct option: C

{\mathrm{K}_2}\mathrm{S}{\mathrm{O}_4} + \mathrm{C}{\mathrm{u}_2}{\mathrm{I}_2} + {\mathrm{I}_2}

Option C is correct because potassium iodide (KI) reacts with copper sulfate (

\mathrm{CuSO_4}

) to form cuprous iodide (

\mathrm{Cu_2I_2}

), potassium sulfate (

\mathrm{K_2SO_4}

), and iodine (

\mathrm{I_2}