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JEE MATHEMATICS MCQ: INCREASING & DECREASING

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Analyzing +4 | -1
The maximum slope of the curve y=12x4−5x3+18x2−19xy = \frac{1}{2}{x^4} - 5{x^3} + 18{x^2} - 19x occurs at the point
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Correct option: A
(2, 2)
Option A (2, 2) is correct. The maximum slope occurs where the second derivative of the curve is zero and the third derivative is negative, which happens at x=2. Substituting x=2 into the original equation gives y=2.

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