JEE MATHEMATICS MCQ: MEAN VALUES THEOREM

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Application +4 | -1

The value of

c

for which the conclusion of Lagrange's theorem holds for the function

f(x)=\sqrt{a^2-x^2}, a>1

on the interval

[1, a]

View answer and explanation

Correct option: C

\sqrt{\frac{a(a+1)}{2}}

Option C (

\sqrt{\frac{{a(a+1)}}{{2}}}

) is the correct value of c, obtained by applying Lagrange's Mean Value Theorem to the given function and interval.

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