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JEE MATHEMATICS MCQ: PAIR OF STRAIGHT LINES

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Application +4 | -1
If the equation 3x2+xy−y2−3x+6y+k=03{x^2} + xy - {y^2} - 3x + 6y + k = 0 represents a pair of straight lines, then the values of kk is
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Correct option: C
-9
Option B (6x+y−19=06x + y - 19 = 0) is correct because it represents the equation of the line that bisects the segment joining the points (-4, 6) and (8, 8) perpendicularly.

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