JEE CHEMISTRY MCQ: CHEMICAL BONDING & MOLECULAR STRUCTURE

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Analyzing +4 | -1

The electronic configuration of

4

elements

K,L,M\,\,\mathrm{and}\,\,N

are,

\begin{array}{l} K = 1{s^2},2{s^2}2{p^1}\,\,\,\,\,L = 1{s^2},2{s^2}2{p^6}\\ M = 1{s^2},2{s^2}2{p^4}\,\,\,\,N = 1{s^2},2{s^2}2{p^3} \end{array}

The element that would form a diatomic molecule with double bond is:

View answer and explanation

Correct option: C

M

Option M (

M

) is correct because the electronic configuration

1{s^2},2{s^2}2{p^4}

indicates that the element needs two more electrons to complete its octet, thus forming a double bond in a diatomic molecule.

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