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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Application +4 | -1
∫−11xtan⁡−1xdx\int\limits_{{-1}}^1 x \tan ^{-1} x d x equals
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Correct option: A
(π2−1)\left(\frac{\pi}{2}-1\right)
Option A ((π2−1)\left(\frac{\pi}{2}-1\right)) is correct because the integral of xtan⁡−1xx \tan^{-1} x from -1 to 1 is equal to π2−1\frac{\pi}{2}-1.

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