JEE CHEMISTRY MCQ: ORGANIC CHEMISTRY-SOME BASIC PRINCIPLES AND TECHNIQUES

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In the hydrocarbon .

_{C{H_3}\,\,\, - }^C\,_{CH\,\, = }^5\,_{CH\,\,\, - }^4\,_{C{H_2} - }^3\,_{C\,\,\, \equiv \,}^2\,_{CH}^1

the state of hybridisation of 1, 3 and 5 are in the following sequence

View answer and explanation

Correct option: B

SP,S{P^3},S{P^2}

Option B (

SP,S{P^3},S{P^2}

) is correct because the hybridizations of carbons 1, 3, and 5 are SP, SP3, and SP2 respectively, based on the number of sigma bonds.

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