If $f\left( x \right) = \left| {x - 1} \right|,\,\,{\rm{then}}\,\,\mathop \smallint \nolimits_0^2 \,\,f\left( x \right)\,\,dx$

JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

1 Easy

1 of 1

Application +4 | -1

f\left( x \right) = \left| {x - 1} \right|,\,\,\mathrm{then}\,\,\int \nolimits_0^2 \,\,f\left( x \right)\,\,dx

View answer and explanation

Correct option: A

\mathrm{1}

The correct answer is A (1) because the integral of the absolute value function |x-1| from 0 to 2 is equal to 1.

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