JEE PHYSICS MCQ: MOTION IN PLANE

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Three balls are projected from the top of a building with equal speeds but at different angles. Balls strike the ground with velocities

{v} 1

v2

and

{v} 3

respectively, then

View answer and explanation

Correct option: C

{v} 1={v} 2={v} 3

Option C (

{v} 1={v} 2={v} 3

) is correct because the speed at which the balls strike the ground depends only on the initial speed and the height, not the angle of projection.

More Questions from MOTION IN PLANE

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\mathrm{\vec P} = \mathrm{\vec A} + \mathrm{\vec B}\,\,\mathrm{and}\,P = A + B.

\mathrm{\vec A}\,and\,\mathrm{\vec B}

0^{\circ}

90^{\circ}

\mathrm{If}\,(\mathbf{a}+3 \mathbf{b}) \cdot(7 \mathbf{a}-5 \mathbf{b})=0

(\mathbf{a}-4 \mathbf{b}) \cdot(7 \mathbf{a}-2 \mathbf{b})=0

\mathbf{a}

\mathbf{b}

\theta

\left(90^{\circ}-\theta\right)

39.2 \mathrm{~ms}^{-1}

50 \mathrm{~m}

{g}=9.8 \mathrm{~ms}^{-2}