JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Easy

1 of 1

Application +4 | -1

If the ratio of the sum of

n

terms of two A.P.s is

(3 n-13):(5 n+21)

, then the ratio of 24 th terms of the two progressions is

View answer and explanation

Correct option: C

1: 2

Option C (1: 2) is correct because the ratio of the 24th terms is found by relating the sum of n terms to the nth term and substituting n=47.

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A=\{1,2,3\}, B=\{3,4\}, C=\{4,5,6\}

{A} \cup({B} \cap {C})

A-(B \cap C)

(B \cup C)-A

a,b,c

a,x,b

b,y,c

{x^2},{b^2},{y^2}

P(x)=1-x+x^2-x^3+\ldots+x^{2012}

y

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y=x-2

\sum\limits_{{i=0}}^{2012} a_i

\log \left(\frac{5 c}{a}\right), \log \left(\frac{3 b}{5 c}\right)

\log \left(\frac{a}{3 b}\right)

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G P

a, b, c

\frac{3}{4}