$\mathop {\lim }\limits_{x \to 0} \frac{{{a^x} + {a^{ - x}} - 2}}{{{x^2}}}$ is equal to

JEE MATHEMATICS MCQ: LIMITS

1 Easy

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Analyzing +4 | -1

\lim\limits_{x \to 0} \frac{{{a^x} + {a^{ - x}} - 2}}{{{x^2}}}

is equal to

View answer and explanation

Correct option: A

{\left( {\log a} \right)^2}

Option C (

a = 1

and

b = - 2

) is correct because by simplifying the expression and taking the limit as x approaches infinity, we find that a = 1 and b = -2.

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