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JEE PHYSICS MCQ: UNITS & MEASUREMENTS

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Analyzing +4 | -1
Suppose refractive index μ\mu is given as μ=A+Bλ2\mu=A+\frac{B}{\lambda^2} where AA and BB are constants and λ\lambda is wavelength, then dimensions of BB are same as that of
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Correct option: D
Area
Option D (Area) is correct because for the equation to be dimensionally consistent, B must have the dimensions of wavelength squared, which is area.

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