NEET UG PHYSICS MCQ: ELECTRO MAGNETIC INDUCTION

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Application +4 | -1

A wire of length

1\,\,m

is moving at a speed of

2\,\,m{s^{ - 1}}

perpendicular to its length and in a homogenous magnetic field of

0.5\,\,T

. The ends of the wire are joined to a circuit of resistance

6\,\,\mathrm{\Omega }

. The rate at which work is being done to keep the wire moving at constant speed is

View answer and explanation

Correct option: B

\frac{1}{6}\,\,W

Option B (

\frac{1}{6}\,W

) is correct because it is calculated by finding the induced emf, current, and then the power required to maintain constant speed against the magnetic force.

More Questions from ELECTRO MAGNETIC INDUCTION

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Assertion (A): Whenever the magnetic flux linked with a closed coil changes there will be an induced emf as well as an induced current.

Reason (R): According to Faraday, the induced emf is inversely proportional to the rate of change of magnetic flux linked with a coil. The coefficient of mutual inductance of two coils is

6\,\,mH

. If the current flowing in one is

2\,\,ampere

, then the induced e.m.f. in the second coil will be The induced emf cannot be produced by: Consider the statements:
(I)If magnetic field,

\mathrm{B = 0}

, then magnetic flux is also zero.
(II)If magnetic flux,

\phi = 0,

then magnetic field is also zero. The coefficient of self inductance of a solenoid is 0.18 mH. If a rod of soft iron of relative permeability 900 is inserted, then the coefficient of self inductance (in mH ) will become nearly: A uniformly wound solenoidal coil of self inductance

1.8 \times {10^{ - 4}}

H and resistance 6 Ω is broken up into two identical coils. These identical coils are then connected in parallel across a 12 V battery of negligible resistance. The time constant of the current in the circuit 