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JEE CHEMISTRY MCQ: AMINES

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Analyzing +4 | -1
Given below are two statements:

Statement I: Aniline reacts with con. H2SO4\mathrm{H}_2 \mathrm{SO}_4, followed by heating at 453−473 K453-473 \mathrm{~K} gives p−\mathrm{p}- aminobenzene sulphonic acid, which gives blood red colour in the 'Lassaigne's test'.
Statement II: In Friedel-Craft's alkylation and acylation reactions, aniline forms salt with the AlCl3\mathrm{AlCl}_3 catalyst. Due to this, nitrogen of aniline acquires a positive charge and acts as deactivating group.

In the light of the above statements, choose the correct answer from the options given below:
View answer and explanation
Correct option: C
Both statement I and statement II are true
The correct answer is C (Both statement I and statement II are true) because aniline does form p-aminobenzene sulfonic acid and gives a positive Lassaigne's test, and it also forms a salt with AlCl3, deactivating the ring.

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