The dipole moment of $HBr$ is $1.6 \times {10^{ - 30}}$ cm and inter – atomic spacing is $1\,\,\mathop {\rm{A}}\limits^{\rm{o}} $. The $\% $ ionic character of $HBr$ is

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JEE CHEMISTRY MCQ: CHEMICAL BONDING & MOLECULAR STRUCTURE

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The dipole moment of

HBr

1.6 \times {10^{ - 30}}

cm and inter – atomic spacing is

1\,\,\mathop \mathrm{A}\limits^\mathrm{o}

. The

\%

ionic character of

HBr

View answer and explanation

Correct option: B

Option B (10) is correct because the percentage ionic character is calculated by dividing the actual dipole moment by the theoretical dipole moment and multiplying by 100.

JEE CHEMISTRY MCQ: CHEMICAL BONDING & MOLECULAR STRUCTURE

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