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JEE PHYSICS MCQ: SYSTEM OF PARTICLES

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A flywheel is making 3000/π3000 / \pi revolutions per minute about its axis. If the moment of inertia of the flywheel about that axis is 400 kgm2400 \,\mathrm{kgm}^2, its rotational kinetic energy is
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Correct option: A
2×106 J2 \times 10^6 \mathrm{~J}
Option A (2×106 J2 \times 10^6 \mathrm{~J}) is correct because it is calculated using the rotational kinetic energy formula with correct angular velocity.

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