JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

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Analyzing +4 | -1

\cos \alpha+2 \cos \beta+3 \cos \gamma=0, \sin \alpha+2 \sin \beta

+3 \sin \gamma=0

and

\alpha+\beta+\gamma=\pi

, then

\sin 3 \alpha+8 \sin 3 \beta+27 \sin 3 \gamma

is equal to

View answer and explanation

Correct option: B

Option B is correct because using complex numbers and the given conditions, it can be shown that

\sin 3 \alpha+8 \sin 3 \beta+27 \sin 3 \gamma = 0

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