JEE MATHEMATICS MCQ: SET THEORY

1 Easy

1 of 1

Analyzing +4 | -1

Let

A=[x: x \in R,|x|<1] B=[x: x \in R,|x-1| \geq 1]

and

A \cup B=R-D

, then the set

\mathrm{D}

is:

View answer and explanation

Correct option: B

[x: 1 \leq x<2]

Option B (

[x: 1 \leq x<2]

) is correct because it represents the set D such that

A \cup B = R - D

, where A and B are defined by the given inequalities.

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2 a_1 a_2 a_3 \ldots . . a_{2006}

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S

a N=\{a n: n \in N: b N=\{n b: n \in N\}

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\}

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F(n)

n

[\mathrm{F}(20) \cap \mathrm{F}(16)] \subseteq \mathrm{F}(\mathrm{y})

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4 \%

A

C

2 \%

A