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JEE MATHEMATICS MCQ: LIMITS

1 Easy
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Analyzing +4 | -1
lim⁡x→+∞20+2x+3x1/32+4x−3+(8x−4)1/3=\lim _{x \rightarrow+\infty} \frac{20+2 \sqrt{x}+3 x^{1 / 3}}{2+\sqrt{4 x-3}+(8 x-4)^{1 / 3}}=
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Correct option: A
1
Option A (1) is correct because after dividing both numerator and denominator by √x, the limit as x approaches infinity is 1.

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