JEE MATHEMATICS MCQ: ELLIPSE

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Application +4 | -1

The locus of points whose polars with respect to the ellipse

\frac{{{x^2}}}{{{a^2}}} + \frac{{{y^2}}}{{{b^2}}} = 1

are at a distance

d

from the centre of the ellipse, is

View answer and explanation

Correct option: B

\frac{{{x^2}}}{{{a^4}}} + \frac{{{y^2}}}{{{b^4}}} = \frac{1}{{{d^2}}}

Option B (

\frac{{{x^2}}}{{{a^4}}} + \frac{{{y^2}}}{{{b^4}}} = \frac{1}{{{d^2}}}

) is correct because it represents the locus of points whose polars are at a distance d from the center of the ellipse.

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\frac{x^2}{144}+\frac{y^2}{81}=1

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O