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JEE PHYSICS MCQ: NUCLEI

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Application +4 | -1
The fossil bone has a 14C:12C^{14}\mathrm{C}{:^{12}}\mathrm{C} ratio, which is [116]\left[ {\frac{1}{{16}}} \right] of that in a living animal bone. If the half-life of 14C^{14}\mathrm{C} is 5730 yr\mathrm{5730 }\,\mathrm{yr}, then the age of the fossil bone is
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Correct option: C
22920 yr\mathrm{22920 }\,\mathrm{yr}
Option C (22920 yr\mathrm{22920 }\,\mathrm{yr}) is correct because the age of the fossil is determined by calculating the number of half-lives that have passed based on the ratio of 14C^{14}\mathrm{C} to 12C^{12}\mathrm{C}.

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