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JEE CHEMISTRY MCQ: CHEMICAL BONDING & MOLECULAR STRUCTURE

1 Easy

1 of 1

Analyzing +4 | -1

Which among the following has only two

\pi

-bonds and no

\sigma

-bond?

View answer and explanation

Correct option: A

\mathrm{C}_2

Option D is correct because the cyclic hydrocarbon with equal C-C bond lengths between 1.34 and 1.54 Å is benzene, which has a C-C-C bond angle of 120° due to sp2 hybridization.

More Questions from CHEMICAL BONDING & MOLECULAR STRUCTURE

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The hybridization in sulphur dioxide is

\mathrm{C}{\mathrm{O}_2}

has the same geometry as:

\left( A \right)\mathrm{HgC}{\mathrm{l}_2},\left( B \right)\mathrm{N}{\mathrm{O}_2},\left( C \right)\mathrm{SnC}{\mathrm{l}_4},\left( D \right){\mathrm{C}_2}{\mathrm{H}_2}

The pair of molecules forming strongest hydrogen bonds are Paramagnetism is shown by Which statement is correct? Assertion (A) :

{BF}_3

is a weaker Lewis acid than

{BCl}_3

.

Reason (R) : The planar

{BF}_3

molecule is stabilised to a greater extent than

{BCl}_3

{B}-X \pi

-bonding.