JEE MATHEMATICS MCQ: PROBABILITY

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Among 15 players, 8 are batsman and 7 are bowlers. The probability that a team is chosen of 6 batsman and 5 bowlers, is

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Correct option: A

\frac{{{\;^8}{C_6} \times {\;^7}{C_5}}}{{{\;^{15}}{C_{11}}}}

Option A (

\frac{{{\;^8}{C_6} \times {\;^7}{C_5}}}{{{\;^{15}}{C_{11}}}}

) is correct because it represents the number of ways to choose 6 batsmen from 8 and 5 bowlers from 7, divided by the total number of ways to choose 11 players from 15.

More Questions from PROBABILITY

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\begin{array}{cccccc}X: & 1 & 2 & 3 & 4 & 5 \\ P(X): & k^2 & 2 k & k & 2 k & 5 k^2\end{array}

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is A bag contains

\left( {2\;n + 1} \right)

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n

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P\left( {A \cap B'} \right) = \frac{3}{{25}}

and

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A

and total of scores on the two dice, in each throw is noted. A wins the game if he throws a total of 6 before

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