$\mathop {\lim }\limits_{x \to 0} \,\frac{{\sin (\pi {{\cos }^2}x)}}{{{x^2}}}\,$ is equal to

JEE MATHEMATICS MCQ: LIMITS

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Application +4 | -1

\lim\limits_{x \to 0} \,\frac{{\sin (\pi {{\cos }^2}x)}}{{{x^2}}}\,

is equal to

View answer and explanation

Correct option: D

\pi

Option D (

\pi

) is correct because using trigonometric identities and limit properties, the given limit simplifies to

\pi

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