The number of electrons in $0.2 \mathrm{~mol}$ of ${Al}^{3+}$ ion is

$0.2 \times \mathrm{N}_{\mathrm{A}}$

$0.1 \times \mathrm{N}_{\mathrm{A}}$

JEE CHEMISTRY MCQ: SOME BASIC CONCEPTS OF CHEMISTRY

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Application +4 | -1

The number of electrons in

0.2 \mathrm{~mol}

{Al}^{3+}

ion is

View answer and explanation

Correct option: D

2 \times \mathrm{N}_{\mathrm{A}}

Option D (

2 \times N_A

) is correct because each Al3+ ion has 10 electrons, and 0.2 moles of Al3+ ions will therefore have 2NA electrons.

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