Let $LL'$ be the latusrectum and S be a focus of the ellipse $\frac{{{x^2}}}{{{a^2}}} + \frac{{{y^2}}}{{{b^2}}} = 1.$ If $\Delta SLL'$ is equilaterial, then the eccentricity of the ellipse is

JEE MATHEMATICS MCQ: ELLIPSE

1 Easy

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Application +4 | -1

Let

LL'

be the latusrectum and S be a focus of the ellipse

\frac{{{x^2}}}{{{a^2}}} + \frac{{{y^2}}}{{{b^2}}} = 1.

\Delta SLL'

is equilaterial, then the eccentricity of the ellipse is

View answer and explanation

Correct option: B

1/\sqrt 3

Option B (

1/\sqrt 3

) is correct because when the triangle SLL' is equilateral, the eccentricity can be derived using the properties of the ellipse and the latus rectum.

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r

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O