JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Easy

1 of 1

Analyzing +4 | -1

2\log x - \log \left( {x + 1} \right) - \log \left( {x - 1} \right)

is equal to

View answer and explanation

Correct option: B

\frac{1}{{{x^2}}} + \frac{1}{{2\;{x^4}}} + \frac{1}{{3\;{x^6}}} + \ldots

Option B (

\frac{1}{{{x^2}}} + \frac{1}{{2\;{x^4}}} + \frac{1}{{3\;{x^6}}} + \ldots

) is the correct expansion after simplifying the logarithmic expression.

More Questions from SEQUENCE OF SERIES

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A=\{1,2,3\}, B=\{3,4\}, C=\{4,5,6\}

{A} \cup({B} \cap {C})

A-(B \cap C)

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a,b,c

a,x,b

b,y,c

{x^2},{b^2},{y^2}

P(x)=1-x+x^2-x^3+\ldots+x^{2012}

y

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y=x-2

\sum\limits_{{i=0}}^{2012} a_i

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\log \left(\frac{a}{3 b}\right)

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\frac{3}{4}