If ${\rm{\vec A}}{\rm{.\vec B}} = 0\,and\,\,{\rm{\vec A}} \times {\rm{\vec B}} = 1$, then ${\rm{\vec A}}\;\,and\,{\rm{\vec B}}$ are

NEET UG PHYSICS MCQ: MOTION IN PLANE

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\mathrm{\vec A}\mathrm{.\vec B} = 0\,and\,\,\mathrm{\vec A} \times \mathrm{\vec B} = 1

, then

\mathrm{\vec A}\;\,and\,\mathrm{\vec B}

are

View answer and explanation

Correct option: A

Perpendicular unit vectors

Option A (Perpendicular unit vectors) is correct because if

\mathrm{\vec A}\mathrm{.\vec B} = 0

and

\mathrm{\vec A} \times \mathrm{\vec B} = 1

, it means the vectors are perpendicular and their magnitudes multiply to 1, implying they are unit vectors.

Practice All Chapter MCQs →

\mathrm{\vec a}\,and\,\mathrm{\vec b}

\mathrm{\vec a}\,and\,\mathrm{\vec b}

\overrightarrow P \,\,.\,\,\overrightarrow Q = 0\,and\,\overrightarrow P \,\, \times \,\,\overrightarrow Q = 0

\overrightarrow Q \,and\,\overrightarrow R

\vec{A}=3 \hat{i}+4 \hat{j}

\vec{B}=6 \hat{i}+8 \hat{j}

A

B

\overrightarrow{\mathrm{A}}

\overrightarrow{\mathrm{B}}

{\cot ^{ - 1}}\left( 2 \right)