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NEET UG PHYSICS MCQ: SYSTEM OF PARTICLES

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A uniform cubical box of side aa is placed on a rough floor and it is to be moved by applying minimum possible force FF at a point which is at a distance bb above its centre of mass. If the coeflicient of friction is μ=0.4\mu=0.4, then what is the maximum possible value of 100×ba100 \times \frac{b}{a} for which the box will not topple before moving?
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Correct option: A
50
Option A is correct. The box will not topple if the torque due to the applied force is less than or equal to the torque due to the weight of the box. This condition leads to the maximum possible value of b/a being 0.5, hence 100 * (b/a) = 50.

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