If $Q_1 \,\&\, Q_2$ be the angle made by tangents to the axis of $y^2=4 x$ from point $P \,\&$ if $Q_1+Q_2=45^{\circ}$ then locus of point ${P}$ is

JEE MATHEMATICS MCQ: PARABOLA

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Application +4 | -1

Q_1 \,\&\, Q_2

be the angle made by tangents to the axis of

y^2=4 x

from point

P \,\&

Q_1+Q_2=45^{\circ}

then locus of point

{P}

View answer and explanation

Correct option: C

y=(x-1)

Option C (y=(x-1)) is correct because using the tangent formula and the given condition

Q_1 + Q_2 = 45^{\circ}

, we can derive the locus of point P as y = x-1.

Practice All Chapter MCQs →

y=x^2

y=-(x-2)^2

P

y^2=16 x

P

P,Q,R

{y^2} = 4x

P

R

Q

PR

(1,0)

y^2+4 x=8

x^2=-16 y

I

{y^2} = 4ax

SP

SQ

PQ,S

SP,l

SQ