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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Analyzing +4 | -1
∑n=1∞2n2+n+1n!\sum \limits_{n = 1}^\infty \frac{{2{n^2} + n + 1}}{{n!}} is equal to
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Correct option: C
6e−16e - 1
Option C (6e−16e - 1) is correct because the series can be decomposed and expressed in terms of the exponential constant e.

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