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JEE PHYSICS MCQ: WAVE OPTICS

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The wave front of a light beam is given by the equation x + 2y + 3z = constant. The angle made by the direction of light with the y-axis is

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Correct option: C

{\cos ^{ - 1}}\left( {\frac{2}{{\sqrt {14} }}} \right)

Option C (

{\cos ^{ - 1}}(\frac{2}{{\sqrt {14} }}))

is correct because the angle is found using the direction vector of the plane and the dot product formula.

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