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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Application +4 | -1
The equation log⁡ex+log⁡e(1+x)=0{\log _e}x + {\log _e}\left( {1 + x} \right) = 0 can be written as
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Correct option: A
x2+x−1=0{x^2} + x - 1 = 0
The correct answer is x2+x−1=0{x^2} + x - 1 = 0 because by using logarithm properties, the equation can be simplified to this quadratic form.

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