Which is the reducing agent in the reaction,$8{{\rm{H}}^ + } + 4{\rm{NO}}_3^ - + 6{\rm{C}}{{\rm{l}}^ - } + {\rm{Sn}}\left( {\rm{s}} \right) \to {\rm{SnCl}}_6^{2 - } + 4{\rm{N}}{{\rm{O}}_2} + 4{{\rm{H}}_2}{\rm{O}}?$

${\rm{Sn}}\left( {\rm{s}} \right)$

${\rm{N}}{{\rm{O}}_2}\left( {\rm{g}} \right)$

JEE CHEMISTRY MCQ: REDOX REACTIONS

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Analyzing +4 | -1

Which is the reducing agent in the reaction,

8{\mathrm{H}^ + } + 4\mathrm{NO}_3^ - + 6\mathrm{C}{\mathrm{l}^ - } + \mathrm{Sn}\left( \mathrm{s} \right) \to \mathrm{SnCl}_6^{2 - } + 4\mathrm{N}{\mathrm{O}_2} + 4{\mathrm{H}_2}\mathrm{O}?

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Correct option: A

\mathrm{Sn}\left( \mathrm{s} \right)

Option A (Sn(s)) is correct because Sn(s) is oxidized from oxidation state 0 to +4, thus it is the reducing agent.

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\mathrm{H}

2 \mathrm{KClO}_3 \longrightarrow 2 \mathrm{KCl}+3 \mathrm{O}_2

\mathrm{HNO}_3

\mathrm{HNO}_3

\mathrm{MnO}_4^{-}(\mathrm{aq})+\mathrm{Br}^{-}(\mathrm{aq})+\mathrm{H}_2 \mathrm{O} \longrightarrow 2 \mathrm{MnO}_2(\mathrm{aq})+\mathrm{BrO}_3^{-}(\mathrm{aq})+2 \mathrm{OH}^{-}(\mathrm{aq})

\mathrm{Br}

-1

+5.