Skip to main content
Back to ELECTRIC FIELDS AND CHARGES

JEE PHYSICS MCQ: ELECTRIC FIELDS AND CHARGES

1 Medium
1 of 1
Application +4 | -1
The force of interaction between two charges q1=6μ  {q_1} = 6\mu \; C and q2=2μ{q_2} = 2\mu C is 12 N. If charge q=−2μq = - 2\mu C is added to each of the charges, then the new force of interaction is
View answer and explanation
Correct option: B
Zero
Option B (Zero) is correct because adding the same charge to both original charges results in the product of the new charges being zero, thus the force is zero.

More Questions from ELECTRIC FIELDS AND CHARGES

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.