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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Analyzing +4 | -1
Let An=(34)−(34)2+(34)3−…+(−1)n−1(34)nA_{n}=\left(\frac{3}{4}\right)-\left(\frac{3}{4}\right)^{2}+\left(\frac{3}{4}\right)^{3}-\ldots+(-1)^{n-1}\left(\frac{3}{4}\right)^{n} and Bn=1−AnB_{n}=1-A_{n}. Then, the least odd natural number pp, so that Bn>AnB_{n}>A_{n}, for all n≥pn \geq p is
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Correct option: C
11
Option C (11) is correct because by analyzing the inequality Bn>AnB_n > A_n and using the G.P. formula, we find that the least odd natural number p satisfying the condition is 11.

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