JEE MATHEMATICS MCQ: LIMITS

1 Easy

1 of 1

Application +4 | -1

\lim _{x \rightarrow 0} \frac{x+\sin 2 x}{x-\sin 2 x}

is equal to

View answer and explanation

Correct option: B

-3

The correct answer is B (-3) because applying L'Hôpital's rule to the limit yields the value -3.

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