Let ${a_1},\,{a_2},...,\,{a_n}$ be a given AP. Whose common difference is an integer and ${{\rm{S}}_{\rm{n}}}\, = {a_{1\,}} + \,{a_2} + ... + {a_n}.$ If ${a_1}\, = \,1,\,\,{a_n}\, = \,300$ and $15 \le n \le 50,$ then the ordered pair $\left( {{S_{n - 4}},\,{a_{n - 4}}} \right)$ is equal to

$\left( {2490,\,\,249} \right)$

$\left( {2480,\,\,249} \right)$

$\left( {2480,\,\,248} \right)$

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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Application +4 | -1

Let

{a_1},\,{a_2},...,\,{a_n}

be a given AP. Whose common difference is an integer and

{\mathrm{S}_\mathrm{n}}\, = {a_{1\,}} + \,{a_2} + ... + {a_n}.

{a_1}\, = \,1,\,\,{a_n}\, = \,300

and

15 \le n \le 50,

then the ordered pair

\left( {{S_{n - 4}},\,{a_{n - 4}}} \right)

is equal to

View answer and explanation

Correct option: D

\left( {2490,\,\,248} \right)

Option D ((2490, 248)) is correct because it calculates the sum and the nth term of the arithmetic progression after determining the common difference and the number of terms.

JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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