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JEE MATHEMATICS MCQ: PERMUTATIONS

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Application +4 | -1
If one test (on screening paper basis) was conducted on Batch A, maximum number of marks is (90×3)=270.4(90 \times 3)=270.4 students get the marks lower than 80 . Coaching institute decide to inform their guardians, that is why their result card were sent to their home. The number of ways, in which all the letters were put in wrong envelopes, is
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Correct option: A
9
Option A (9) is correct because the number of ways to put all 4 letters in the wrong envelopes is calculated using the derangement formula, which results in 9.

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