JEE MATHEMATICS MCQ: LIMITS

1 Easy

1 of 1

Application +4 | -1

\lim \limits_{{x \rightarrow \pi / 6}} \frac{2 \sin ^2 x+\sin x-1}{2 \sin ^2 x-3 \sin x+1}=

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Correct option: B

-3

Option B (-3) is correct because after factoring and simplifying the limit expression, substituting x = pi/6 yields -3.

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