The decreasing order of the second ionization energy of $K$, ${\rm{Ca}}$ and ${\rm{Ba}}$ is:

Back to CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES

NEET UG CHEMISTRY MCQ: CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES

1 Hard

1 of 1

Analyzing +4 | -1

The decreasing order of the second ionization energy of

K

\mathrm{Ca}

and

\mathrm{Ba}

is:

View answer and explanation

Correct option: A

\mathrm{K} > Ca > Ba

Option A (

\mathrm{K} > Ca > Ba

) is correct because after the first ionization, K attains a noble gas configuration, requiring significantly more energy for the second ionization. Ca and Ba lose electrons from the s-orbital.

More Questions from CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES

Practice All Chapter MCQs →

The elements with zero electron affinity are S-I:

\mathrm{Cu}^{+2}

paramagnetic.

S-II: All the orbitals present in

\mathrm{Cu}^{+2}

ion are doubly occupied. Which of the following is the most electropositive element? The law of Octaves is not applicable to: Assertion (A): Mendeleev's arranged elements in horizontal rows and vertical columns.
Reason (R): Mendeleev's ignored the order of atomic weight thinking that the atomic measurements might be incorrect. Which of the following electronic configuration does not belong to same block as others?