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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Analyzing +4 | -1
Let f:[−1,2]→[0,∞)f:[-1,2] \rightarrow[0, \infty) be a continuous function such that f(x)=f(1−x)f(x)=f(1-x) for all x∈[−1,2]x \in[-1,2] Let R1=∫−12xf(x) dxR_1=\int\limits_{{-1}}^2 x f(x) \,d x; and R2R_2 be the area of the region bounded by y=f(x),x=−1,x=2y=f(x), x=-1, x=2 and the xx-axis. Then,
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Correct option: C
2R1=R22 R_1=R_2
Option C (2R1=R22 R_1=R_2) is correct because by using the property of definite integrals and the given condition f(x)=f(1−x)f(x) = f(1-x), we can relate R1R_1 and R2R_2.

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