JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Analyzing +4 | -1

\alpha=\int\limits_{0}^1 e^{9 x+3 \tan ^{-1} x}\left(\frac{12+9 x^2}{1+x^2}\right) d x

, where

\tan ^{-1} x

takes only principal values, then the value of

\left(\log _e|1+\alpha|-\frac{3 \pi}{4}\right)

, is

View answer and explanation

Correct option: A

Option A (9) is correct because it is found by substituting and simplifying the given integral and then taking the logarithm.

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