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NEET UG PHYSICS MCQ: NUCLEI

1 Hard
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Application +4 | -1
Consider a nuclear fusion reaction A+B→CA+B \rightarrow C. Nucleus AA is moving with KE=5 MeV\mathrm{KE}=5\, \mathrm{MeV} and collides with nucleus BB moving with KE=3 MeV\mathrm{KE}=3 \,\mathrm{MeV} and forms nucleus CC in excited state. Find the KE (in MeV\mathrm{MeV}) of CC nucleus just after its formation given that its excitation energy is 10.3 MeV.10.3 \mathrm{~MeV}. Take masses of nuclei of A,BA, B and CC as 25.0,10.0,34.9925.0,10.0,34.99 amu respectively. [Take : 1 amu=930 MeV1 \,\mathrm{amu}=930 \,\mathrm{MeV}]
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Correct option: A
7
Option A (7) is correct because the kinetic energy of the combined nucleus C is equal to the total kinetic energy of the reactants minus the excitation energy of the product.

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