Question

If $A = \left\{ {x:\frac{\pi }{6} \le x \le \frac{\pi }{3}} \right\}$ and $f\left( x \right) = \cos x - x\left( {1 + x} \right)$, then $f\left( A \right)$ is equal to

Accepted Answer

$\left[ {\frac{1}{2} - \frac{\pi }{3}\left( {1 + \frac{\pi }{3}} \right),\,\,\frac{{\sqrt 3 }}{2} - \frac{\pi }{6}\left( {1 + \frac{\pi }{6}} \right)} \right]$

Answer

$\left[ { - \frac{\pi }{3},\;\, - \frac{\pi }{6}} \right]$

Answer

$\left[ {\frac{\pi }{6},\;\,\frac{\pi }{3}} \right]$

Answer

$\left[ {\frac{1}{2} + \frac{\pi }{3}\left( {1 - \frac{\pi }{3}} \right),\,\,\frac{{\sqrt 3 }}{2} + \frac{\pi }{6}\left( {1 - \frac{\pi }{6}} \right)} \right]$

JEE MATHEMATICS MCQ: TRANSFORMATIONS

More Questions from TRANSFORMATIONS