JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

1 Easy

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Application +4 | -1

The equation

8 \sec ^2 \theta-6 \sec \theta+1=0

has -

View answer and explanation

Correct option: D

No roots

Option D (No roots) is correct because the equation leads to

\sec \theta

values that are not possible, as the absolute value of

\sec \theta

must be greater than or equal to 1.

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\tan \alpha=\frac{p}{q}

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\triangle A B C

C

{\sin ^6}\,\,\theta + {\cos ^6}\,\,\theta + 3{\sin ^2}\,\,\theta \,\,{\cos ^2}\,\,\theta

\sin ^2 \frac{A}{2}+\sin ^2 \frac{B}{2}+\sin ^2 \frac{C}{2}=

\sin ^2(A / 2)+\sin ^2(B / 2)-\sin ^2(C / 2)=