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JEE CHEMISTRY MCQ: BIOMOLECULES

1 Hard

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Application +4 | -1

In an amino acid, the carboxyl group ionizes at

\mathrm{p}{K_{{a_1}}} = 2.34

and ammonium ion at

\mathrm{p}{K_{{a_2}}} = 9.6

. The isoelectric point of the amino acid is at pH

View answer and explanation

Correct option: A

5.97

Option C (

\ - \pi - 3{\sin ^{ - 1}}x

) is correct because given the range of x,

{\sin ^{ - 1}}(3x - 4x^3)

simplifies to

\ - \pi - 3{\sin ^{ - 1}}x

.

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